[C_ST49-易] 字串取代(C++)

[C_ST49-易] 字串取代

問題描述：
目前有一篇文章，在文章中有些字串內容不雅或不適當，而現在為了美觀我們要改掉這些不雅或不適當的字眼，請依據字串修改對照表來取代。

字串修改對照表
不雅字	取代字
hate	love
stupid	smart
angry	happy
dirty	clean

輸入說明：
輸入一文章，將字串修改對照表中列為不雅字的單字取代掉。
※文章字元長度(包含空白)<=1000。
範例：
輸出輸入測試資料

Sample Input:	Sample Output:
To tell you the truth, I hate to do it,The sailor was stupid with liquor,They were drinking and telling dirty jokes.He'll be angry to find that nothing has been done.	To tell you the truth, I love to do it,The sailor was smart with liquor,They were drinking and telling clean jokes.He'll be happy to find that nothing has been done.
To tell you the truth, I hate to do it,The sailor was stupid with liquor,They were drinking and telling dirty jokes.He'll be angry to find that nothing has been done. To tell you the truth, I hate to do it,The sailor was stupid with liquor,They were drinking and telling dirty jokes.He'll be angry to find that nothing has been done.	To tell you the truth, I love to do it,The sailor was smart with liquor,They were drinking and telling clean jokes.He'll be happy to find that nothing has been done.To tell you the truth, I love to do it,The sailor was smart with liquor,They were drinking and telling clean jokes.He'll be happy to find that nothing has been done.

1. #include<iostream>  
2. #include<string>  
3. #include<algorithm>  
4. #include<map>  
5. using namespace std;  
6. int main()  
7. {  
8.     // [C_ST49-易] 字串取代  
9.     string s;  
10.     getline(cin, s);  
11.     string p[] = { "hate", "stupid", "angry", "dirty" };  
12.     string q[] = { "love", "smart", "happy", "clean" };  
13.     for (int i = 0; i < 4; i++)  
14.     {  
15.         string p1 = p[i];  
16.         string q1 = q[i];  
17.         int fpos = 0;  
18.         while (1)  
19.         {  
20.             fpos = s.find(p1, fpos);  
21.             if (fpos != string::npos)  
22.             {  
23.                 s.replace(fpos, p1.size(), q1);  
24.                 fpos = fpos + p1.size();  
25.             }  
26.             else  
27.                 break;  
28.         }  
29.     }  
30.     cout << s << endl;  
31.     return  0;  
32. }